The Reasoning section of every competitive exam includes questions from the topic “Mathematical Operators/ Fictitious Symbols”. Here, we are uploading different types of questions which will surely help you in the upcoming Railways & SSC Exams. This topic deals with the questions on basics of fundamental operations — addition, subtraction, multiplication and division. Sometimes, the questions involving these operations are set using artificial symbols. The candidate has to substitute the real signs and solve the questions accordingly to get the answer.
Basic Concepts & Short Tricks of Fictitious Symbol questions
Different types of questions covered in this chapter are as follows
Symbol Substitution
Balancing the Equation
Interchange of Signs and Numbers
Trick Based Mathematical Operations
Note:- While solving a mathematical expression, proceed according to the rule BODMAS — i.e., Brackets, Of, Division, Multiplication, Addition, Subtraction.
Example:
(36 -12) ÷4 + 6 + 2 x 3 = 24 ÷ 4 + 6 + 2 x 3 (Solving Bracket)
= 6 + 6 + 2 x 3 (Solving Division)
= 6+6+6 (Solving Multiplication)
= 18 (Solving Addition)
Type 1: Symbol Substitution
In this type of question, a candidate is provided with the substitutes for various mathematical symbols followed by a question involving calculation of an expression or choosing the correct/ incorrect equation. The candidate is required to put in the real signs in the given equation and then solve the questions as required.
Ex 1: if ‘×’ means ‘-’, ‘÷’ means ‘+’, + means ‘×’, then 18 × 5 ÷ 5 +6 is equal to
58
49
43
37
Solution: (c)
Change of symbols according to the question,
? = 18 × 5 ÷ 5 + 6 = 18 – 5 + 5 × 6
= 18 – 5 + 30 = (13 + 30) = 43
Type 2: Balancing the Equation
In this type of questions, the signs in one of the alternatives are required to fill up the blank spaces in order to balance the given equation
Ex: Choose the correct option in order to balance the following equation.
24 6 12 16 = 0
- , + and +
÷, + and ÷
-, - and -
÷, + and –
Solution: (d)
From Option (d)
Hence, option (d) is correct.
Type 3: Interchange of Signs and Numbers
In this type of questions, the given equation becomes correct and fully balanced when either two signs of the equation or both the numbers and the signs of the equation are interchanged. The candidate is required to find the correct pair of signs and numbers from the given options.
Ex: Choose the correct interchange option in order to make the given equation correct
10 – 2 +9 × 2 ÷ 4 = 19
÷,+,x and -
-,+,x and +
÷, ÷,÷ and ×
×,÷,× and ÷
Solution: (a)
Let us check the options one by one
From option (a),
As options (a) gives us the correct answer. Hence, there is no need to check other options
Type 4: Trick Based Mathematical Operations
The questions are based on simple mathematical operations that do not follow a universal rule. These questions can be based on several different patterns.
Ex: If 9 × 5 × 2 = 529 and 4 × 7 × 2 = 724, then 3 × 9 × 8 = ?
983
839
938
893
Solution: (a)
= 983
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